x=10x^2-18x

Solution for x=10x^2-18x equation:

x=10x^2-18x

We move all terms to the left:

x-(10x^2-18x)=0

We get rid of parentheses

-10x^2+x+18x=0

We add all the numbers together, and all the variables

-10x^2+19x=0

a = -10; b = 19; c = 0;
Δ = b2-4ac
Δ = 192-4·(-10)·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-19}{2*-10}=\frac{-38}{-20}
=1+9/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+19}{2*-10}=\frac{0}{-20}
=0
$